Oracle QUERIES2

51) Display the name of the empployee who earns highest salary.

SQL>select ename from emp where sal=(select max(sal) from emp);

52) Display the employee number and name for employee working as clerk and

earning highest salary among clerks.

SQL>select empno,ename from emp where where job='CLERK'

and sal=(select max(sal) from emp where job='CLERK');

53) Display the names of salesman who earns a salary more than the highest

salary of any clerk.

SQL>select ename,sal from emp where job='SALESMAN' and sal>(select

max(sal) from emp

where job='CLERK');

54) Display the names of clerks who earn a salary more than the lowest

salary of any salesman.

SQL>select ename from emp where job='CLERK' and sal>(select min(sal)

from emp where job='SALESMAN');

Display the names of employees who earn a salary more than that of

Jones or that of salary grether than that of scott.

SQL>select ename,sal from emp where sal>

(select sal from emp where ename='JONES')and sal> (select sal from emp

where ename='SCOTT');

55) Display the names of the employees who earn highest salary in their

respective departments.

SQL>select ename,sal,deptno from emp where sal in(select max(sal) from

emp group by deptno);

56) Display the names of the employees who earn highest salaries in their

respective job groups.

SQL>select ename,sal,job from emp where sal in(select max(sal) from emp

group by job)

57) Display the employee names who are working in accounting department.

SQL>select ename from emp where deptno=(select deptno from dept where

dname='ACCOUNTING')

58) Display the employee names who are working in Chicago.

SQL>select ename from emp where deptno=(select deptno from dept where

LOC='CHICAGO')

59) Display the Job groups having total salary greater than the maximum

salary for managers.

SQL>SELECT JOB,SUM(SAL) FROM EMP GROUP BY JOB HAVING SUM(SAL)>(SELECT

MAX(SAL) FROM EMP WHERE JOB='MANAGER');

60) Display the names of employees from department number 10 with salary

grether than that of any employee working in other department.

SQL>select ename from emp where deptno=10 and sal>any(select sal from

emp where deptno not in 10).

61) Display the names of the employees from department number 10 with

salary greater than that of all employee working in other departments.

SQL>select ename from emp where deptno=10 and sal>all(select sal from

emp where deptno not in 10).

62) Display the names of the employees in Uppercase.

SQL>select upper(ename)from emp

63) Display the names of the employees in Lowecase.

SQL>select lower(ename)from emp

64) Display the names of the employees in Propercase.

SQL>select initcap(ename)from emp;

65) Display the length of Your name using appropriate function.

SQL>select length('name') from dual

66) Display the length of all the employee names.

SQL>select length(ename) from emp;

67) select name of the employee concatenate with employee number.

SQL>select ename||empno from emp;

68) User appropriate function and extract 3 characters starting from 2

characters from the following string 'Oracle'. i.e the out put should be 'ac'.

SQL>select substr('oracle',3,2) from dual

69) Find the First occurance of character 'a' from the following string i.e

'Computer Maintenance Corporation'.

SQL>SELECT INSTR('Computer Maintenance Corporation','a',1) FROM DUAL

70) Replace every occurance of alphabhet A with B in the string Allens(use

translate function)

SQL>select translate('Allens','A','B') from dual

71) Display the informaction from emp table.Where job manager is found it

should be displayed as boos(Use replace function).

SQL>select replace(JOB,'MANAGER','BOSS') FROM EMP;

72) Display empno,ename,deptno from emp table.Instead of display department

numbers display the related department name(Use decode function).

SQL>select empno,ename,decode(deptno,10,'ACCOUNTING',20,'RESEARCH',30,'SALES',40,'OPRATIONS') from emp;

73) Display your age in days.

SQL>select to_date(sysdate)-to_date('10-sep-77')from dual

74) Display your age in months.

SQL>select months_between(sysdate,'10-sep-77') from dual

75) Display the current date as 15th Augest Friday Nineteen Ninety Saven.

SQL>select to_char(sysdate,'ddth Month day year') from dual

76) Display the following output for each row from emp table.

scott has joined the company on wednesday 13th August ninten nintey.

SQL>select ENAME||' HAS JOINED THE COMPANY ON '||to_char(HIREDATE,'day

ddth Month year') from EMP;

77) Find the date for nearest saturday after current date.

SQL>SELECT NEXT_DAY(SYSDATE,'SATURDAY')FROM DUAL;

78) Display current time.

SQL>select to_char(sysdate,'hh:MM:ss') from dual.

79) Display the date three months Before the current date.

SQL>select add_months(sysdate,3) from dual;

80) Display the common jobs from department number 10 and 20.

SQL>select job from emp where deptno=10 and job in(select job from emp

where deptno=20);

81) Display the jobs found in department 10 and 20 Eliminate duplicate jobs.

SQL>select distinct(job) from emp where deptno=10 or deptno=20

(or)

SQL>select distinct(job) from emp where deptno in(10,20);

82) Display the jobs which are unique to department 10.

SQL>select distinct(job) from emp where deptno=10

83) Display the details of those who do not have any person working under them.

SQL>select e.ename from emp,emp e where emp.mgr=e.empno group by

e.ename having count(*)=1;

84) Display the details of those employees who are in sales department and

grade is 3.

SQL>select * from emp where deptno=(select deptno from dept where

dname='SALES')and sal between(select losal from salgrade where grade=3)and

(select hisal from salgrade where grade=3);

85) Display those who are not managers and who are managers any one.

i)display the managers names

SQL>select distinct(m.ename) from emp e,emp m where m.empno=e.mgr;

ii)display the who are not managers

SQL>select ename from emp where ename not in(select distinct(m.ename)

from emp e,emp m where m.empno=e.mgr);

86) Display those employee whose name contains not less than 4 characters.

SQL>select ename from emp where length(ename)>4;

87) Display those department whose name start with "S" while the location

name ends with "K".

SQL>select dname from dept where dname like 'S%' and loc like '%K';

88) Display those employees whose manager name is JONES.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and

e.ename='JONES';

89) Display those employees whose salary is more than 3000 after giving 20%

increment.

SQL>select ename,sal from emp where (sal+sal*.2)>3000;

90) Display all employees while their dept names;

SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno

91) Display ename who are working in sales dept.

SQL>select ename from emp where deptno=(select deptno from dept where

dname='SALES');

92) Display employee name,deptname,salary and comm for those sal in between

2000 to 5000 while location is chicago.

SQL>select ename,dname,sal,comm from emp,dept where sal between 2000

and 5000

and loc='CHICAGO' and emp.deptno=dept.deptno;

93)Display those employees whose salary greter than his manager salary.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.sal>e.sal

94) Display those employees who are working in the same dept where his

manager is work.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and

p.deptno=e.deptno;

95) Display those employees who are not working under any manager.

SQL>select ename from emp where mgr is null

96) Display grade and employees name for the dept no 10 or 30 but grade is

not 4 while joined the company before 31-dec-82.

SQL>select ename,grade from emp,salgrade where sal between losal and

hisal and deptno in(10,30) and grade<>4 and hiredate<'31-DEC-82';

97) Update the salary of each employee by 10% increment who are not eligiblw for commission.

SQL>update emp set sal=sal+sal*10/100 where comm is null;

98) SELECT those employee who joined the company before 31-dec-82 while

their dept location is newyork or Chicago.

SQL>SELECT EMPNO,ENAME,HIREDATE,DNAME,LOC FROM EMP,DEPT

WHERE (EMP.DEPTNO=DEPT.DEPTNO)AND

HIREDATE <'31-DEC-82' AND DEPT.LOC IN('CHICAGO','NEW YORK');

99) DISPLAY EMPLOYEE NAME,JOB,DEPARTMENT,LOCATION FOR ALL WHO ARE WORKINGAS MANAGER?

SQL>select ename,JOB,DNAME,LOCATION from emp,DEPT where mgr is not

null;

100) DISPLAY THOSE EMPLOYEES WHOSE MANAGER NAME IS JONES? --

[AND ALSO DISPLAY THEIR MANAGER NAME]?

SQL> SELECT P.ENAME FROM EMP E, EMP P WHERE E.EMPNO=P.MGR AND

E.ENAME='JONES';

101) Display name and salary of ford if his salary is equal to hisal of his

grade

a)select ename,sal,grade from emp,salgrade where sal between losal and

hisal and ename ='FORD' AND HISAL=SAL;

102) Display employee name,job,depart name ,manager name,his grade and make

out an under department wise?

SQL>SELECT E.ENAME,E.JOB,DNAME,EMP.ENAME,GRADE FROM EMP,EMP

E,SALGRADE,DEPT

WHERE EMP.SAL BETWEEN LOSAL AND HISAL AND EMP.EMPNO=E.MGR

AND EMP.DEPTNO=DEPT.DEPTNO ORDER BY DNAME

103) List out all employees name,job,salary,grade and depart name for every

one in the company except 'CLERK'.Sort on salary display the highest salary?

SQL>SELECT ENAME,JOB,DNAME,SAL,GRADE FROM EMP,SALGRADE,DEPT WHERE

SAL BETWEEN LOSAL AND HISAL AND EMP.DEPTNO=DEPT.DEPTNO AND JOB

NOT IN('CLERK')ORDER BY SAL ASC;

104) Display the employee name,job and his manager.Display also employee who

are without manager?

SQL>select e.ename,e.job,eMP.ename AS Manager from emp,emp e where

emp.empno(+)=e.mgr

105) Find out the top 5 earners of company?

SQL>SELECT DISTINCT SAL FROM EMP E WHERE 5>=(SELECT COUNT(DISTINCT SAL)

FROM EMP A WHERE A.SAL>=E.SAL)ORDER BY SAL DESC;

106) Display name of those employee who are getting the highest salary?

SQL>select ename from emp where sal=(select max(sal) from emp);

107) Display those employee whose salary is equal to average of maximum and

minimum?

SQL>select ename from emp where sal=(select max(sal)+min(sal)/2 from

emp);

108) Select count of employee in each department where count greater than 3?

SQL>select count(*) from emp group by deptno having count(deptno)>3

109) Display dname where at least 3 are working and display only department

name?

SQL>select distinct d.dname from dept d,emp e where d.deptno=e.deptno

and 3>any (select count(deptno) from emp group by deptno)

110) Display name of those managers name whose salary is more than average

salary of his company?

SQL>SELECT E.ENAME,EMP.ENAME FROM EMP,EMP E

WHERE EMP.EMPNO=E.MGR AND E.SAL>(SELECT AVG(SAL) FROM EMP);